Option is an option, all right, seems like doing no harm to the original game, it requires an effort to implement and hecen it should make sense and add a different approach to the game that would comprimise that implementation effort. I can not agree that game will be more balanced with that option, knowing the number of cards the opponents have give a good hint to choose correct strategy, with that option, the number of expected enemy-bonuses varies a lot. I personally would not choose that option, and vote against to spend time to implement it currently, thinking about all other urgent fixes needed.
Apart from these, I made a quick calculation of probabilities without taking black into consideration, correct me if I am wrong.
XXX refers to 3-same color set and RGB refers to
3 cards:
RGB 6/27
XXX 3/27
non 18/27
4 cards:
RGB 36/81
XXX 27/81
non 18/81
with 5cards:
RGB 126/243
XXX 153/243
(these two do not add up to one, since they overlap. this is indeed a quite nice counting question, or lets say a math riddle (votazap..
), and I am not completely sure about my answer, could someone validate these? )
So, it seems like having the 3-same color set is less likely than having 3-different color set, when there are 3 or 4 cards in hand, but it gives less bonus according to the proposal. A bit contrary to what you expect from being lucky.
Only waiting till 5 gives a slight advantage of probability to have a 3-different set.
Taking black card into consideration, this really becomes quite advanced mathematical question. I remember about a 1/20 percentage of chance for black to appear. Can you tell me Vexer, what is the exact probability distribution for cards?
Option is an option, all right, seems like doing no harm to the original game, it requires an effort to implement and hecen it should make sense and add a different approach to the game that would comprimise that implementation effort. I can not agree that game will be more balanced with that option, knowing the number of cards the opponents have give a good hint to choose correct strategy, with that option, the number of expected enemy-bonuses varies a lot. I personally would not choose that option, and vote against to spend time to implement it currently, thinking about all other urgent fixes needed.
Apart from these, I made a quick calculation of probabilities without taking black into consideration, correct me if I am wrong.
XXX refers to 3-same color set and RGB refers to
3 cards:
RGB 6/27
XXX 3/27
non 18/27
4 cards:
RGB 36/81
XXX 27/81
non 18/81
with 5cards:
RGB 126/243
XXX 153/243
(these two do not add up to one, since they overlap. this is indeed a quite nice counting question, or lets say a math riddle (votazap.. :)), and I am not completely sure about my answer, could someone validate these? )
So, it seems like having the 3-same color set is less likely than having 3-different color set, when there are 3 or 4 cards in hand, but it gives less bonus according to the proposal. A bit contrary to what you expect from being lucky.
Only waiting till 5 gives a slight advantage of probability to have a 3-different set.
Taking black card into consideration, this really becomes quite advanced mathematical question. I remember about a 1/20 percentage of chance for black to appear. Can you tell me Vexer, what is the exact probability distribution for cards?