While being no expert in statistical analysis or mathematical probabilities, I see that vikingo's new suggestion is in-keeping with this threads intention (reduce the chances of against-the-odds wins by the defenders when vastly outnumbered).

vikingo1337

The D12 Dodecahedron die. It has twelve sides; useful for, say, any attacker with more than 12 troops.

I see from the DnD dice link you provided that the 12 sided dice is numbered from 1 to 12.

With that number system, I don't know how it can be incorporated in the programming to fight against 6 sided dice. First it would be better if it was a dice with 2 of everything from 1 to 6, but this wouldn't improve the chances of the attacker rolling a 6, over a standard 6 sided dice.

Another way to do it is to incorporate a reverse of dough_boy's defence dice suggestion and fix the attack dice ability / odds of not rolling the worst numbers, so making something like 3 X

**6**'s, 3 X

**5**'s, 2 X

**4**'s, 2 X

**3**'s, 1 X

**2** and 1 X

**1**.

Whatever we end up deciding on, I think it's best to unify on what we want the outcome to be.

This thread is solely related to the amount of complaints about

*paraphrasing* "how can 1 or 2 defending troops kill 10 or 12 attacking troops and lose none"

__It's probably best to get some sort of survey started.__**Vastly Outnumbered** should really signify the amount considered suitable to guarantee a win with little to no resistance.

1) What number of attacking troops constitutes "vastly outnumbered" against 1 defender?

2) What ratio of attacking troops constitutes "vastly outnumbered" against all defenders?

Before we can ask other questions, we need to know these figures.

While being no expert in statistical analysis or mathematical probabilities, I see that vikingo's new suggestion is in-keeping with this threads intention (reduce the chances of against-the-odds wins by the defenders when vastly outnumbered).
[quote=vikingo1337]The D12 Dodecahedron die. It has twelve sides; useful for, say, any attacker with more than 12 troops.[/quote]
I see from the DnD dice link you provided that the 12 sided dice is numbered from 1 to 12.
With that number system, I don't know how it can be incorporated in the programming to fight against 6 sided dice. First it would be better if it was a dice with 2 of everything from 1 to 6, but this wouldn't improve the chances of the attacker rolling a 6, over a standard 6 sided dice.
Another way to do it is to incorporate a reverse of dough_boy's defence dice suggestion and fix the attack dice ability / odds of not rolling the worst numbers, so making something like 3 X [b]6[/b]'s, 3 X [b]5[/b]'s, 2 X [b]4[/b]'s, 2 X [b]3[/b]'s, 1 X [b]2[/b] and 1 X [b]1[/b].
Whatever we end up deciding on, I think it's best to unify on what we want the outcome to be.
This thread is solely related to the amount of complaints about [i]paraphrasing[/i] "how can 1 or 2 defending troops kill 10 or 12 attacking troops and lose none"
[u]It's probably best to get some sort of survey started.[/u]
[i][b]Vastly Outnumbered[/b][/i] should really signify the amount considered suitable to guarantee a win with little to no resistance.
1) What number of attacking troops constitutes "vastly outnumbered" against 1 defender?
2) What ratio of attacking troops constitutes "vastly outnumbered" against all defenders?
Before we can ask other questions, we need to know these figures.